(16x^2+20x-6)/(2x^2-9x-56)

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Solution for (16x^2+20x-6)/(2x^2-9x-56) equation:


D( x )

2*x^2-(9*x)-56 = 0

2*x^2-(9*x)-56 = 0

2*x^2-(9*x)-56 = 0

2*x^2-9*x-56 = 0

2*x^2-9*x-56 = 0

DELTA = (-9)^2-(-56*2*4)

DELTA = 529

DELTA > 0

x = (529^(1/2)+9)/(2*2) or x = (9-529^(1/2))/(2*2)

x = 8 or x = -7/2

x in (-oo:-7/2) U (-7/2:8) U (8:+oo)

(16*x^2+20*x-6)/(2*x^2-(9*x)-56) = 0

(16*x^2+20*x-6)/(2*x^2-9*x-56) = 0

16*x^2+20*x-6 = 0

2*(8*x^2+10*x-3) = 0

8*x^2+10*x-3 = 0

DELTA = 10^2-(-3*4*8)

DELTA = 196

DELTA > 0

x = (196^(1/2)-10)/(2*8) or x = (-196^(1/2)-10)/(2*8)

x = 1/4 or x = -3/2

2*(x+3/2)*(x-1/4) = 0

2*x^2-9*x-56 = 0

2*x^2-9*x-56 = 0

DELTA = (-9)^2-(-56*2*4)

DELTA = 529

DELTA > 0

x = (529^(1/2)+9)/(2*2) or x = (9-529^(1/2))/(2*2)

x = 8 or x = -7/2

(x+7/2)*(x-8) = 0

(2*(x+3/2)*(x-1/4))/((x+7/2)*(x-8)) = 0

( x+3/2 )

x+3/2 = 0 // - 3/2

x = -3/2

( x-1/4 )

x-1/4 = 0 // + 1/4

x = 1/4

x in { -3/2, 1/4 }

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